Optimal. Leaf size=133 \[ -\frac {(a+b x)^{5/2} (4 a B+3 A b)}{4 a x}+\frac {5 b (a+b x)^{3/2} (4 a B+3 A b)}{12 a}+\frac {5}{4} b \sqrt {a+b x} (4 a B+3 A b)-\frac {5}{4} \sqrt {a} b (4 a B+3 A b) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )-\frac {A (a+b x)^{7/2}}{2 a x^2} \]
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Rubi [A] time = 0.06, antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {78, 47, 50, 63, 208} \begin {gather*} -\frac {(a+b x)^{5/2} (4 a B+3 A b)}{4 a x}+\frac {5 b (a+b x)^{3/2} (4 a B+3 A b)}{12 a}+\frac {5}{4} b \sqrt {a+b x} (4 a B+3 A b)-\frac {5}{4} \sqrt {a} b (4 a B+3 A b) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )-\frac {A (a+b x)^{7/2}}{2 a x^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 47
Rule 50
Rule 63
Rule 78
Rule 208
Rubi steps
\begin {align*} \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx &=-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {\left (\frac {3 A b}{2}+2 a B\right ) \int \frac {(a+b x)^{5/2}}{x^2} \, dx}{2 a}\\ &=-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {(5 b (3 A b+4 a B)) \int \frac {(a+b x)^{3/2}}{x} \, dx}{8 a}\\ &=\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {1}{8} (5 b (3 A b+4 a B)) \int \frac {\sqrt {a+b x}}{x} \, dx\\ &=\frac {5}{4} b (3 A b+4 a B) \sqrt {a+b x}+\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {1}{8} (5 a b (3 A b+4 a B)) \int \frac {1}{x \sqrt {a+b x}} \, dx\\ &=\frac {5}{4} b (3 A b+4 a B) \sqrt {a+b x}+\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {1}{4} (5 a (3 A b+4 a B)) \operatorname {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )\\ &=\frac {5}{4} b (3 A b+4 a B) \sqrt {a+b x}+\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}-\frac {5}{4} \sqrt {a} b (3 A b+4 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )\\ \end {align*}
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Mathematica [C] time = 0.03, size = 56, normalized size = 0.42 \begin {gather*} \frac {(a+b x)^{7/2} \left (b x^2 (4 a B+3 A b) \, _2F_1\left (2,\frac {7}{2};\frac {9}{2};\frac {b x}{a}+1\right )-7 a^2 A\right )}{14 a^3 x^2} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.19, size = 128, normalized size = 0.96 \begin {gather*} \frac {\sqrt {a+b x} \left (60 a^3 B+45 a^2 A b-100 a^2 B (a+b x)-75 a A b (a+b x)+24 A b (a+b x)^2+32 a B (a+b x)^2+8 B (a+b x)^3\right )}{12 b x^2}-\frac {5}{4} \left (4 a^{3/2} b B+3 \sqrt {a} A b^2\right ) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.41, size = 209, normalized size = 1.57 \begin {gather*} \left [\frac {15 \, {\left (4 \, B a b + 3 \, A b^{2}\right )} \sqrt {a} x^{2} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (8 \, B b^{2} x^{3} - 6 \, A a^{2} + 8 \, {\left (7 \, B a b + 3 \, A b^{2}\right )} x^{2} - 3 \, {\left (4 \, B a^{2} + 9 \, A a b\right )} x\right )} \sqrt {b x + a}}{24 \, x^{2}}, \frac {15 \, {\left (4 \, B a b + 3 \, A b^{2}\right )} \sqrt {-a} x^{2} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (8 \, B b^{2} x^{3} - 6 \, A a^{2} + 8 \, {\left (7 \, B a b + 3 \, A b^{2}\right )} x^{2} - 3 \, {\left (4 \, B a^{2} + 9 \, A a b\right )} x\right )} \sqrt {b x + a}}{12 \, x^{2}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.33, size = 155, normalized size = 1.17 \begin {gather*} \frac {8 \, {\left (b x + a\right )}^{\frac {3}{2}} B b^{2} + 48 \, \sqrt {b x + a} B a b^{2} + 24 \, \sqrt {b x + a} A b^{3} + \frac {15 \, {\left (4 \, B a^{2} b^{2} + 3 \, A a b^{3}\right )} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} - \frac {3 \, {\left (4 \, {\left (b x + a\right )}^{\frac {3}{2}} B a^{2} b^{2} - 4 \, \sqrt {b x + a} B a^{3} b^{2} + 9 \, {\left (b x + a\right )}^{\frac {3}{2}} A a b^{3} - 7 \, \sqrt {b x + a} A a^{2} b^{3}\right )}}{b^{2} x^{2}}}{12 \, b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 110, normalized size = 0.83 \begin {gather*} 2 \left (\sqrt {b x +a}\, A b +2 \sqrt {b x +a}\, B a +\frac {\left (b x +a \right )^{\frac {3}{2}} B}{3}+\left (-\frac {5 \left (3 A b +4 B a \right ) \arctanh \left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{8 \sqrt {a}}+\frac {\left (-\frac {9 A b}{8}-\frac {B a}{2}\right ) \left (b x +a \right )^{\frac {3}{2}}+\left (\frac {7}{8} A a b +\frac {1}{2} B \,a^{2}\right ) \sqrt {b x +a}}{b^{2} x^{2}}\right ) a \right ) b \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.76, size = 155, normalized size = 1.17 \begin {gather*} \frac {1}{24} \, {\left (\frac {15 \, {\left (4 \, B a + 3 \, A b\right )} \sqrt {a} \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{b} - \frac {6 \, {\left ({\left (4 \, B a^{2} + 9 \, A a b\right )} {\left (b x + a\right )}^{\frac {3}{2}} - {\left (4 \, B a^{3} + 7 \, A a^{2} b\right )} \sqrt {b x + a}\right )}}{{\left (b x + a\right )}^{2} b - 2 \, {\left (b x + a\right )} a b + a^{2} b} + \frac {16 \, {\left ({\left (b x + a\right )}^{\frac {3}{2}} B + 3 \, {\left (2 \, B a + A b\right )} \sqrt {b x + a}\right )}}{b}\right )} b^{2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.42, size = 162, normalized size = 1.22 \begin {gather*} \left (2\,A\,b^2+4\,B\,a\,b\right )\,\sqrt {a+b\,x}-\frac {\left (B\,a^2\,b+\frac {9\,A\,a\,b^2}{4}\right )\,{\left (a+b\,x\right )}^{3/2}-\left (B\,a^3\,b+\frac {7\,A\,a^2\,b^2}{4}\right )\,\sqrt {a+b\,x}}{{\left (a+b\,x\right )}^2-2\,a\,\left (a+b\,x\right )+a^2}+\frac {2\,B\,b\,{\left (a+b\,x\right )}^{3/2}}{3}+2\,b\,\mathrm {atan}\left (\frac {2\,b\,\left (3\,A\,b+4\,B\,a\right )\,\sqrt {-\frac {25\,a}{64}}\,\sqrt {a+b\,x}}{5\,B\,a^2\,b+\frac {15\,A\,a\,b^2}{4}}\right )\,\left (3\,A\,b+4\,B\,a\right )\,\sqrt {-\frac {25\,a}{64}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 81.71, size = 488, normalized size = 3.67 \begin {gather*} - \frac {10 A a^{4} b^{2} \sqrt {a + b x}}{- 8 a^{4} - 16 a^{3} b x + 8 a^{2} \left (a + b x\right )^{2}} + \frac {6 A a^{3} b^{2} \left (a + b x\right )^{\frac {3}{2}}}{- 8 a^{4} - 16 a^{3} b x + 8 a^{2} \left (a + b x\right )^{2}} + \frac {3 A a^{3} b^{2} \sqrt {\frac {1}{a^{5}}} \log {\left (- a^{3} \sqrt {\frac {1}{a^{5}}} + \sqrt {a + b x} \right )}}{8} - \frac {3 A a^{3} b^{2} \sqrt {\frac {1}{a^{5}}} \log {\left (a^{3} \sqrt {\frac {1}{a^{5}}} + \sqrt {a + b x} \right )}}{8} - \frac {3 A a^{2} b^{2} \sqrt {\frac {1}{a^{3}}} \log {\left (- a^{2} \sqrt {\frac {1}{a^{3}}} + \sqrt {a + b x} \right )}}{2} + \frac {3 A a^{2} b^{2} \sqrt {\frac {1}{a^{3}}} \log {\left (a^{2} \sqrt {\frac {1}{a^{3}}} + \sqrt {a + b x} \right )}}{2} + \frac {6 A a b^{2} \operatorname {atan}{\left (\frac {\sqrt {a + b x}}{\sqrt {- a}} \right )}}{\sqrt {- a}} - \frac {3 A a b \sqrt {a + b x}}{x} + 2 A b^{2} \sqrt {a + b x} - \frac {B a^{3} b \sqrt {\frac {1}{a^{3}}} \log {\left (- a^{2} \sqrt {\frac {1}{a^{3}}} + \sqrt {a + b x} \right )}}{2} + \frac {B a^{3} b \sqrt {\frac {1}{a^{3}}} \log {\left (a^{2} \sqrt {\frac {1}{a^{3}}} + \sqrt {a + b x} \right )}}{2} + \frac {6 B a^{2} b \operatorname {atan}{\left (\frac {\sqrt {a + b x}}{\sqrt {- a}} \right )}}{\sqrt {- a}} - \frac {B a^{2} \sqrt {a + b x}}{x} + 4 B a b \sqrt {a + b x} + B b^{2} \left (\begin {cases} \sqrt {a} x & \text {for}\: b = 0 \\\frac {2 \left (a + b x\right )^{\frac {3}{2}}}{3 b} & \text {otherwise} \end {cases}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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